Jet Washer Nozzle

Jet Washer Nozzle

Question of the pressure, the right formula?

Finding the right formula to solve the following. Having a litle trouble with my notes and text books. I have calculated so far. A washing jet is running in loss of 53% since coming into office. The power of water is 736W at 42.05 Bar pumping 0095 gallons of water per second. What I need to calculate the diameter of the nozzle. Can anyone tell me in the right direction please? Thank you very much for your excellent thank you, but how to deal with the length of the pipe because it is not known and also Coëffic viscosity? Cheers

42.05 bar = 1406.79 meters from the head of 0.095 liters / second = 5797 cubic centimeters per second 0095 liter / Second = 0.003354893 cubic meters / second hole speed v = sqrt (2 xgxh) 8.02x = sqrt (1406.79) = 300 fps experience, I decided 6 as a typical rate of adoption a hole 6 Q = A x V x A = Q / (.6 x V) = 0.003354893 ft ³ / sec / (.6 * 300 m / s) A = 1.8638294 x 10E-5 m² A = 1.7315542143 mm square A = Pi * (D / 2) ^ 2 ring hole diameter = 1.485 mm (I did it very quickly to check my work)

Can you help me? wish list of non-profit agencies, May 24 The following is a wish list of items and volunteer organizations Nonprofit opportunitiesfrom Racine County. They have received bylocal nonprofit organizations.