Wagon Bottom Floor
Wagon Bottom Floor
I need help with these physics problems?
A box of 36 kg, initially at rest, is dragged along the ground by pulling a rope inclined 15 ° friction coefficients horizontal.The above are static and kinetic microseconds respectively = 0.62 and μk = 0.53, and the voltage chain is F = 222 n. (a) What is the magnitude of the normal force? N (b) What is the minimum horizontal force needed to start the drawer? N (c) What is the magnitude of the frictional force acting on the box? N (d) What is the magnitude of the acceleration of the box? --------------------------------------- M/s2 -------- ---------------------------- A 40.0 kg wagon is towed by a steep hill from 18.8 ° to the horizontal. The towline is parallel to the slope and a voltage of 140 N in the same. Assume that the wagon starts from rest at the bottom of the hill, the friction and neglect. What is the speed of car is in motion after 75 meters on the hill? m / s ----------------------------------- ------------ -----------------------------------
Consider forces in tray: gravity = g = M * N * friction or can be static or kinetic 222 N rope that has two components: Horizontal: COS (15) * 222 Vertical: Unknown (15) * 222 a) The normal force is the resultant of vertical forces on the block: N = 30 * 9.8-Sin (15) * 222 = 236.54N b) the horizontal force to overcome static friction is = 236.54 *. 62 = 146.65N c) the horizontal component of the chain tension is 214.44N and the box is moving. The force of friction is the normal time, the coefficient kinetic friction =. 53 * = 125.37N The 236.54N Unlike the horizontal component of the chain is the acceleration of the box: F = m * A = (214,44-125,37) / 30 A = 2.97M / s ^ 2 --------------- ----------- ----------- to the second problem I'll use the conservation of energy. The work done by the towline = F * D also gain potential energy is m * g * sin (18.8) * D The energy difference kinetics is 1 / 2 * m * v ^ 2 F * DM * g * sin (18.8) * D = .5 * m * v ^ 2 v = sqrt ((F * DM * g * sin (18, 
* d) * 2 / m) to the plug all the numbers for v = sqrt ((140 * 75-40 * 9.8 * sin (18.8) * 75) * 2 / 40) = 7.16 m / sj
Vanderbilt Mini Gold Rush "We all thought (gold) is found in abundance in the mountains," says Oliver James Fisk. "They came on horseback, by car or Buckboard, trains and donkey, with all their worldly possessions. "
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